helpz

[Saman]

help

[Saman]

err

(F(Us) >or equal to (G)(Mass of b)) / mass of car ?

[Saman]

(F ) (Us) = (G)(Mass of b))

F = (G*Mass b)/Us

F = MA so

(G*Mass b)/Us = Mass of b * A

(G)/Us = A


?

[Boombostik]

It amazes me that you know all that shit, yet you couldn't spell my name right even with it 2 posts above yours.

^^i think what we just saw was level 14 pwnage of Saman.^^

[DarkSpoon]

It amazes me that you know all that shit, yet you couldn't spell my name right even with it 2 posts above yours.

^^i think what we just saw was level 14 pwnage of Saman.^^

its pretty elementary physics. that being said i didnt remember it but thats because i took the class 4 years ago.

[Diddlez]

I haven't touched physics in quite some time, so everything I'm about to type is more than likely irrelevant to your problem, but I'm going to give it a shot anyway.

coefficient of friction is: u = Fr/Fn, whereas Fr is the force required to move the object and Fn is the normal force.

acceleration is: Fr = ma, whereas m is the mass and Fr is the force required.

to simplify, we can make one equation out of this: u = ma/Fn. From here, if this is even correct or relevant to your problem, I don't know what to do since we don't have the acceleration, normal force, or mass.


When you do figure this out though, please post the answer and how it is done. I really CBF forgeting everything I once knew about physics, calculus, etc.


EDIT: Go ahead and disregard anything I said. I definately didn't take into account the fact that there are two different objects wtih seperate masses. If you still can't figure it out I can go through my physics book and see if I can remember how the fuck its done.

[Saman]

i was right on my third post

A = G/Us